We can force grep to only display matches that are either at the start or the end of a line. This command returns: 2 medium eggs. Grep NOT 7. I wish it only to return lines that DO NOT contain 1234 at the end. -v option is for invert match. Start and End of Lines. Grep to return lines not containing a character Hello , this is my first topic cause I need your little help I got .txt file, and I want to find lines without letter 'a', so im writing: grep "[^a]" list.txt (list.txt is the file of course) and i have no idea why it's not working because it shows lines with a. Without -v, it would output only the lines in which grep does appear. I'm using GNU grep 2.5.4. grep generally does not work very well for doing a positive and a negative search in one invocation. 250g golden caster sugar. The grep command allows you to display text that does not match a pattern. To print files that do not contain extends SomethingSomething anywhere, use the -L option: grep -L -E 'extends[[:space:]]+SomethingSomething' FILENAME… Some versions of grep do not have the -L option (it is not specified by POSIX). grep -L "sl.h" *.c. I'm trying to get Grep to print all lines in a txt file that do not contain the numbers 834. For example, display all the lines except those that contains the keyword “Sales”. The file names are listed, not the matching lines. The awk solution is what I would use, but a slightly smaller process to launch is sed and it can produce the same results, but by substituting the PATH= part of the line with "", i.e.. sed -n 's/^Path=//p' file The -n overrides seds default behavior of 'print all lines' (so -n = no print), and to print a line, we add the p character after the substition. To do this, we will assume that liquid ingredients are measured in mls: grep -v “ml” muffin_recipe.txt. egrep -i '12-12. Grep NOT using grep -v. Using grep -v you can simulate the NOT conditions. As long as your filenames do not contain spaces, tabs, newline or wildcard characters, and if your grep supports the -L option, you can do it as follows: $ cat file1 stringA stringC $ cat file2 stringA stringB $ grep -L stringB $(grep -l stringA file?) i.e It matches all the lines except the given pattern. Any lines that contain “Word1” or “Word2” will be excluded from the printed results. You can also use grep directly on files just as before as well: grep -v -e "Word1" -e "Word2" example.txt. For instance, print all lines that do not contain the word par by using the following command: grep -v par /path/to/file 9 How to list only the names of matching files When I try "grep [^834] file.txt" it still prints all the lines containing 834 but just doesn't highlight them. Another approach is to separate what to exclude with grep by using a pipe to separate each match, like so: grep -Ev "word1|word2" example.txt See man grep for details.. As far as the grep utility is itself concerned, it's unimportant that the pattern grep passed to it as an argument is the same as its name. And of course, we can look for files that don’t contain the search term. Let’s retrieve a list of all the ingredients which are not liquid. The -L (files without match) option does just that. Do not forget to use the backslash before the pipe character.. 400g self raising flour Currently, this is my workaround. grep -v 'pattern1' filename. Users may make use of the -v option to print inverts the match, which means it would match only those lines that do not contain the given word. 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